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x=6x^2+5x
We move all terms to the left:
x-(6x^2+5x)=0
We get rid of parentheses
-6x^2+x-5x=0
We add all the numbers together, and all the variables
-6x^2-4x=0
a = -6; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·(-6)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*-6}=\frac{0}{-12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*-6}=\frac{8}{-12} =-2/3 $
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